Bug #16949 Updated: mysql_query SELECT returns Resource ID

ID: 16949 Updated by: daniel@php.net Reported By: Vipervirus@Angelfire.com Status: Bogus Bug Type: *General Issues Operating System: ? PHP Version: 4.1.2 New Comment: maybe because it's spelled mysql_QUERY and not mysql_EURY. I asked you kindly no to use the bug reporting form for support questions and instead move to the mailing lists. Here's the link again: http://www.php.net/support.php -daniel Previous Comments: ------------------------------------------------------------------------ [2002-05-01 18:48:26] Vipervirus@Angelfire.com I didn't post here intending to ask for help, I was posting a bug because $sql = mysql_query("SELECT * FROM users"); works just fine but $sql = mysql_eury("SELECT * FROM users WHERE name = '$user'"); doesn't work I've tried this on completely diff servers and got the same result ------------------------------------------------------------------------ [2002-05-01 16:37:57] daniel@php.net I give some help anyway. Vipervirus, mysql_query returns the connection id. You must use mysql_fetch_array() to get the values. Please have a look at the example provided in the manual: http://www.php.net/manual/en/ref.mysql.php or http://www.php.net/manual/en/function.mysql-fetch-array.php which has some shorter examples. good luck. Next time please consult the "PHP General" mailinglist: http://www.php.net/support.php ------------------------------------------------------------------------ [2002-05-01 16:23:26] derick@php.net The bug system is not the appropriate forum for asking support questions. For a list of a range of more appropriate places to ask for help using PHP, please visit http://www.php.net/support.php ------------------------------------------------------------------------ [2002-05-01 16:23:24] Vipervirus@Angelfire.com I've been trying for a week now to fix this, finally gave up on it: $sql = mysql_query("SELECT pass FROM users WHERE name = '$user'"); echo $sql . "<br>"; when ran, $sql = Resource ID #2 instead of the actual value, I couldn't get any help from #php on irc.gamesnet.net ------------------------------------------------------------------------ [2002-05-01 16:22:30] Vipervirus@Angelfire.com I've been trying for a week now to fix this, finally gave up on it: $sql = mysql_query("SELECT pass FROM users WHERE name = '$user'"); echo $sql[pass] . "<br>"; when ran, $sql = Resource ID #2 instead of the actual value, I couldn't get any help from #php on irc.gamesnet.net ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=16949&edit=1