Bug #16045 Updated: count($array) logical error

ID: 16045 Updated by: php-bugs@lists.php.net Reported By: dennispopel@lycos.com -Status: Feedback +Status: No Feedback Bug Type: *General Issues Operating System: All PHP Version: 4.1.1 New Comment: No feedback was provided for this bug for over a month, so it is being suspended automatically. If you are able to provide the information that was originally requested, please do so and change the status of the bug back to "Open". Previous Comments: ------------------------------------------------------------------------ [2002-03-13 15:45:18] torben@php.net FWIW, I used the following script and got the correct results: <?php error_reporting(E_ALL); $x = array(1); echo "Count: " . count($x) . "\n"; unset($x[0]); echo "Count: " . count($x) . "\n"; ?> Results: Count: 1 Count: 0 This is on version 4.2.0-dev. and 4.1.2. What does this script produce for you? Torben ------------------------------------------------------------------------ [2002-03-13 15:11:08] dennispopel@lycos.com Hello, Funny logical error: if we have a simple variable, say $x = 1 then count($x) == 1, which is "natural" (I don't think so) And if we have an array $x[0] = 1; count($x) == 1, but after UnSet($x[0]) we still have count($x) = 1! This leads to a very special kind of logical errors which are really hard to track. My suggestion: either: introduce explicit type system (with unions, structs and arrays ;) or: disable count on variables ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=16045&edit=1