#31010 [Opn]: echo a variable that was unset before breaks output
| From: | lars_stegelitz at col dot wunderman dot com | Date: | Tue, 07 Dec 2004 15:39:05 +0000 |
| Subject: | #31010 [Opn]: echo a variable that was unset before breaks output | ||
| References: | 1 | Groups: | php.bugs |
| Request: | Send a blank email to php-bugs+get-69888@lists.php.net to get a copy of this message | ||
ID: 31010
User updated by: lars_stegelitz at col dot wunderman dot com
Reported By: lars_stegelitz at col dot wunderman dot com
Status: Open
Bug Type: Output Control
Operating System: Windows
PHP Version: 4.3.9
New Comment:
addition:
The error-suppression operator (@) in the __set/__get methods should be
omitted to see a warning in standard cases. However, it makes no
difference in case of the mentioned error...
Previous Comments:
------------------------------------------------------------------------
[2004-12-07 16:31:21] lars_stegelitz at col dot wunderman dot com
Description:
------------
When trying to echo an variable that was previously unset, no output at
all is shown. I wrote a small test case (see below)
Reproduce code:
---------------
class Test
{
var $values;
function Test() {
$this->values = array();
}
function __get($key, &$value) {
$value = @$this->values[$key];
return true;
}
function __set($key, $value) {
$this->values[$key] = @$value;
return true;
}
}
overload('Test');
$test = new Test();
$test->xyz = "test";
echo "<br/>1. {$test->xyz}";
unset($test->values['xyz']);
echo "<br/>2. {$test->xyz}";
Expected result:
----------------
1. test
Notice: Undefined variable: xyz in <sourcecode> on line <x>
2.
Actual result:
--------------
Nothing. No output at all. No warning or error in log files or on
screen. Not even the echo *before* unsetting the variable shows up.
------------------------------------------------------------------------
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Edit this bug report at http://bugs.php.net/?id=31010&edit=1