#31927 [Bgs->Opn]: in_array() not working with array containing strings as needle

ID: 31927 User updated by: bart at mediawave dot nl Reported By: bart at mediawave dot nl -Status: Bogus +Status: Open Bug Type: Arrays related Operating System: WinXP PHP Version: 5CVS-2005-02-11 (dev) New Comment: The documentation clearly states: in_array -- Checks if a "value" exists in an array It doesn't say: in_array -- Checks if a "variable" exists in an array An array itself isn't a value. It's a variable containing a collection of values. So, one would expect that in_array checks if all these "values" exist in the haystack. (Regardless of the containing variable type/structure) It shouldn't check if a variable exists in the haystack. The exact match behaviour in your example should only happen when the parameter strict is set. (In my opinion at least) Previous Comments: ------------------------------------------------------------------------ [2005-02-11 20:52:14] tony2001@php.net No bug here: in_array() looks for exact match. This code works fine: <?php $a = array(array("NT", "Linux"), array("Irix", "Linux"), "OS2"); if (in_array(array("NT", "Linux"), $a)) { echo "NT Linux found\n"; } ?> ------------------------------------------------------------------------ [2005-02-11 05:53:04] bart at mediawave dot nl Description: ------------ in_array() doesn't work with an array containing strings (larger then one character) as a needle. Reproduce code: --------------- <?php $a = array(array("Mac", "NT"), array("Irix", "Linux"), "OS2"); if (in_array(array("NT", "Linux"), $a)) { echo "NT Linux found\n"; } if (in_array(array("XP", "Unix"), $a)) { echo "XP Unix found\n"; } if (in_array("OS2", $a)) { echo "OS2 found\n"; } ?> Expected result: ---------------- NT Linux found OS2 found Actual result: -------------- OS2 found ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=31927&edit=1