Bug #17180 Updated: Operator Precedence

ID: 17180 Updated by: derick@php.net Reported By: sitnikov@infonet.ee Status: Analyzed -Bug Type: Scripting Engine problem +Bug Type: Documentation problem PHP Version: 4.2.0 New Comment: Marking this as a doc problem. Previous Comments: ------------------------------------------------------------------------ [2002-05-14 13:46:58] phpclub@digiways.com Actually this is a bug, since in PHP manual it's clearly stated that ! operator has a priority over = operator. > It makes no sense to assign anything to NOT(a variable), > so PHP takes care of that by > changing the precedence a little in this case. In other words - if user makes a mistake and writes illegal code, PHP takes care about that and makes this code work (but in a way different from what developer has expected). Also if you consider any other programming languages, if you write a code which should not compile by language specifications (like the above code in PHP), no compiler will try to "take care" of that. If you insist on that "care", then you definetely have to reflect that in the manual, otherwise it's nothing but a bug. ------------------------------------------------------------------------ [2002-05-13 18:30:31] sitnikov@infonet.ee This behaviour is capable to confuse the developer and if this is "features" it must be documented in manual. ------------------------------------------------------------------------ [2002-05-13 18:20:14] manuzhai@php.net Well, but it's stupid to do something like that. It makes no sense to assign anything to NOT(a variable), so PHP takes care of that by changing the precedence a little in this case. ------------------------------------------------------------------------ [2002-05-13 17:56:54] sitnikov@infonet.ee Yes, I want ASSIGN value to $a and check assigned value. But parser must say: "parser error", becouse it can not assign value to constant. Please reopen. ------------------------------------------------------------------------ [2002-05-13 17:48:54] manuzhai@php.net "if (!$a = foo(FALSE))" --> you're assigning the output of foo(FALSE) to $a "if (!$a == foo(FALSE))" --> you're comparing !$a and foo(FALSE) ------------------------------------------------------------------------ The remainder of the comments for this report are too long. To view the rest of the comments, please view the bug report online at http://bugs.php.net/17180 -- Edit this bug report at http://bugs.php.net/?id=17180&edit=1