#32088 [Opn]: Reference fails after use of unset() on array
| From: | pollita@php.net | Date: | Thu, 19 May 2005 18:52:28 +0000 |
| Subject: | #32088 [Opn]: Reference fails after use of unset() on array | ||
| References: | 1 | Groups: | php.bugs |
| Request: | Send a blank email to php-bugs+get-79228@lists.php.net to get a copy of this message | ||
ID: 32088
Updated by: pollita@php.net
Reported By: karl at posmaster dot com dot au
Status: Open
Bug Type: Zend Engine 2 problem
Operating System: *
PHP Version: 5CVS-2005-02-28
New Comment:
Even more fun: Try this variant and you'll see that $fluff not only
gets reset to NULL, it gets completely unset.
<?php
$stuff = array('one','two');
$fluff = &$stff;
var_dump($stuff);
var_dump($fluff);
foreach ($stuff as $key => &$value) {
if($key==0){
unset ($stuff[$key]);
}else{
$value='This should appear below in the var_dump() because
$value
is passed by reference';
}
}
var_dump($stuff);
var_dump($fluff);
?>
Previous Comments:
------------------------------------------------------------------------
[2005-03-01 00:50:34] karl at posmaster dot com dot au
Although I can use a workaround for this problem (and in the meantime I
have), this is still a bug in php isn't it?
After using unset() on the array, in the loop, the reference breaks.
------------------------------------------------------------------------
[2005-02-28 22:57:00] tony2001@php.net
You are modifying array in the foreach loop.
Consider using for/while instead of foreach.
See this code:
<?php
$stuff = array('one','two');
foreach ($stuff as $key => &$value) {
$value='This should appear below in the var_dump() because $value
is passed by reference';
}
var_dump($stuff);
?>
------------------------------------------------------------------------
[2005-02-28 22:49:56] karl at posmaster dot com dot au
- &$value is a refernce used in the foreach loop.
- If the unset is commented out, the reference to $stuff[1] as $value
on the second iteration of the loop works.
- The call to unset() on the first iteration breaks the reference
Actaul Output:
array(1) { [1]=> string(3) "two" }
Expected Output
array(1) { [1]=> string(3) "This should appear below in the var_dump()
because $value is passed by reference" }
<?php
$stuff = array('one','two');
foreach ($stuff as $key => &$value) {
if($key==0){
unset ($stuff[$key]);
}else{
$value='This should appear below in the var_dump() because $value
is passed by reference';
}
}
var_dump($stuff);
?>
------------------------------------------------------------------------
[2005-02-28 20:18:52] sniper@php.net
What reference? Please give the _EXACT_ expected result.
(and shorten the example script..)
------------------------------------------------------------------------
[2005-02-27 22:51:05] karl at posmaster dot com dot au
No, the bug is still present. The reference that should be present is
still broken.
------------------------------------------------------------------------
The remainder of the comments for this report are too long. To view
the rest of the comments, please view the bug report online at
http://bugs.php.net/32088
--
Edit this bug report at http://bugs.php.net/?id=32088&edit=1