#33090 [Asn->Csd]: mysql_prepare doesn't return an error
| From: | andrey@php.net | Date: | Sat, 21 May 2005 09:36:57 +0000 |
| Subject: | #33090 [Asn->Csd]: mysql_prepare doesn't return an error | ||
| References: | 1 | Groups: | php.bugs |
| Request: | Send a blank email to php-bugs+get-79305@lists.php.net to get a copy of this message | ||
ID: 33090
Updated by: andrey@php.net
Reported By: georg@php.net
-Status: Assigned
+Status: Closed
Bug Type: MySQLi related
Operating System: all
PHP Version: 5.0.4
Assigned To: georg
New Comment:
This bug has been fixed in CVS.
Snapshots of the sources are packaged every three hours; this change
will be in the next snapshot. You can grab the snapshot at
http://snaps.php.net/.
Thank you for the report, and for helping us make PHP better.
Previous Comments:
------------------------------------------------------------------------
[2005-05-21 10:37:26] georg@php.net
Description:
------------
In later versions of libmysqlclient 4.1 and 5.0 the api
call mysql_stmt_close also clears mysql->net.error*
values.
This affects that mysql_prepare doesn't return an error
with current version of libmysql.
Reproduce code:
---------------
<?php
$mysql = new mysqli("localhost", "user", "password",
"test");
if (!($stmt = $mysql->prepare("this will never work"))) {
printf("Error: %s\n", $mysql->error);
}
$mysql->close();
?>
Expected result:
----------------
Error: You have an error in your SQL syntax; check the
manual that corresponds to your MySQL server version for
the right syntax to use near 'this will never work' at
line 1
Actual result:
--------------
Error:
------------------------------------------------------------------------
--
Edit this bug report at http://bugs.php.net/?id=33090&edit=1