#33535 [Opn->Bgs]: $_SERVER['argv'] returns an unusefull array

From: Date: Fri, 01 Jul 2005 14:30:03 +0000
Subject: #33535 [Opn->Bgs]: $_SERVER['argv'] returns an unusefull array
References: 1  Groups: php.bugs 
Request: Send a blank email to php-bugs+get-81268@lists.php.net to get a copy of this message 
 ID:               33535
 Updated by:       tony2001@php.net
 Reported By:      cristian dot zuddas at gmail dot com
-Status:           Open
+Status:           Bogus
 Bug Type:         Variables related
 Operating System: Linux
 PHP Version:      4.3.11
 New Comment:

Thank you for taking the time to write to us, but this is not
a bug. Please double-check the documentation available at
http://www.php.net/manual/ and the instructions on how to
report
a bug at http://bugs.php.net/how-to-report.php

Because in command line arguments are passed in different way and
"a=1&b=2" syntax is used only in URLs.

See details here: http://www.php.net/manual/en/features.commandline.php



Previous Comments:
------------------------------------------------------------------------

[2005-07-01 16:17:42] cristian dot zuddas at gmail dot com

Description:
------------
The var. $_SERVER['argv'] returns an array with only ONE element, that
contains all the query string. I don't think is correct... why the var.
contains an array with only one string, and not directly a (less
expensive) string?

Reproduce code:
---------------
print_r($_SERVER['argv']);

Expected result:
----------------
string type:   l=26&p=5&g=fsd

OR

Array
(
    [0] => l=26
    [1] => p=5
    [2] => g=fsd
)

Actual result:
--------------
Array
(
    [0] => l=26&p=5&g=fsd
)


------------------------------------------------------------------------


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