Bug #17432 Updated: PHP ignores a exit-command
| From: | mfischer@php.net | Date: | Sun, 26 May 2002 09:16:19 +0000 |
| Subject: | Bug #17432 Updated: PHP ignores a exit-command | ||
| References: | 1 | Groups: | php.bugs |
| Request: | Send a blank email to php-bugs+get-8577@lists.php.net to get a copy of this message | ||
ID: 17432
Updated by: mfischer@php.net
Reported By: e05@slashdot.ch
Status: Bogus
Bug Type: Scripting Engine problem
Operating System: Microsoft Windows 2000 SP2
PHP Version: 4.2.1
New Comment:
It's not "illogical". It's simply the way it works and won't change,
you'll have to live with it.
Scripts are completely parsed *before* they're executed. That's a fact.
If the script can't be parsed, it can't be executed.
Calling missing function is something else, it's a run-time behaviour,
that's why this works.
Previous Comments:
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[2002-05-26 05:15:58] derick@php.net
A undefined functionis not a _parse_ error. Function names are
evaluated at runtime in the Zend engine (well, uh, sometimes :), so
it's quite logical from a techincal point of view.
Derick
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[2002-05-26 05:12:57] correction@nospam.please
I think it´s illogical.
Why?
If you call an function which doesn´t exists, it works.
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[2002-05-26 05:09:09] e05@slashdot.ch
I think it´s illogical.
Why?
If you call an function which doesn´t exists, it works.
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[2002-05-26 04:09:04] derick@php.net
A SCript is parse before it is executed. If it can not be parsed
correctly due to a parse error, it will not get executed at all, and
thus your exit(1) call has no effect here.
Not a bug -> bogus
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[2002-05-26 03:34:48] e05@slashdot.ch
I wrote a script with an error, and to ignore it I write an
exit-command before. But PHP ignores it.
A script that shows this bug:
<?php
phpinfo();
exit(1);
if(
phpinfo();
?>
--
My configuration:
Apache 1.3.24 (win32-build from httpd.apache.org)
PHP 4.2.1 (offical win32 build)
PHP runs as Apache module.
--
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Edit this bug report at http://bugs.php.net/?id=17432&edit=1