#35084 [Opn->Fbk]: when using reference to array, then current() returns always first element

From: Date: Thu, 03 Nov 2005 10:57:40 +0000
Subject: #35084 [Opn->Fbk]: when using reference to array, then current() returns always first element
References: 1  Groups: php.bugs 
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 ID:               35084
 Updated by:       derick@php.net
 Reported By:      margus at zone dot ee
-Status:           Open
+Status:           Feedback
 Bug Type:         Scripting Engine problem
 Operating System: SuSE 9.0
 PHP Version:      4.4.1
 New Comment:

Please try using this CVS snapshot:

  http://snaps.php.net/php4-STABLE-latest.tar.gz
 
For Windows:
 
  http://snaps.php.net/win32/php4-win32-STABLE-latest.zip


Previous Comments:
------------------------------------------------------------------------

[2005-11-03 11:57:04] margus at zone dot ee

OS is SuSE 9.0

------------------------------------------------------------------------

[2005-11-03 11:51:49] margus at zone dot ee

Description:
------------
I have reference to array and iterating through the array using
current()/next() loop

The problem is, that $element = current($arr_ref) returns always the
first element in array regardless of multiple next($arr_ref) calls
before current(...)

-----

It worked in php4.4.0. At the moment the only workaround is to replace
everywhere in code:
  $element = current ($arr_ref)
to
  $element = current(& $arr_ref);

Reproduce code:
---------------
$a = array('foot', 'bike');

reset ($a);
next($a);
echo "A:" . current ($a) . "<BR>";


$b =& $a;

reset ($b);
next($b);
echo "B:" . current ($b) . "<BR>";

Expected result:
----------------
A:bike
B:bike

Actual result:
--------------
A:bike
B:foot


------------------------------------------------------------------------


-- 
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