#35086 [Opn->Fbk]: socket_read does not return empty string after receiving '\n'

From: Date: Tue, 08 Nov 2005 08:00:27 +0000
Subject: #35086 [Opn->Fbk]: socket_read does not return empty string after receiving '\n'
References: 1  Groups: php.bugs 
Request: Send a blank email to php-bugs+get-87829@lists.php.net to get a copy of this message 
 ID:               35086
 Updated by:       sniper@php.net
 Reported By:      jelte dot werkhoven at cruisetravel dot nl
-Status:           Open
+Status:           Feedback
 Bug Type:         Sockets related
 Operating System: GNU/Linux (SuSE 10.0)
 PHP Version:      4.4.1
 New Comment:

Please try using this CVS snapshot:

  http://snaps.php.net/php5-latest.tar.gz
 
For Windows:
 
  http://snaps.php.net/win32/php5-win32-latest.zip




Previous Comments:
------------------------------------------------------------------------

[2005-11-08 08:49:34] jelte dot werkhoven at cruisetravel dot nl

... 

I expect it to return "ACK", then return " " because of the '\n' and
break the while loop, which it doesn't. As far as I understand from the
manual it should.

------------------------------------------------------------------------

[2005-11-07 15:30:06] sniper@php.net

So what's wrong in this? Of course it's 4 chars. 
ACK\n == 4 chars.


------------------------------------------------------------------------

[2005-11-07 09:31:28] jelte dot werkhoven at cruisetravel dot nl

Oh and it doesn't break the while-loop.

------------------------------------------------------------------------

[2005-11-07 09:30:21] jelte dot werkhoven at cruisetravel dot nl

CODE:

echo "Reading daemon response:\n";
while( $out = socket_read($socket, 2048, PHP_NORMAL_READ) ) {
	//if( strncmp( $out, 'ACK', 3 ) == 0 ) break;	
	var_dump( $out );
}

RESULT:

OK got socket.
Attempting to connect to '127.0.0.1' on port '8001'...OK got
connection.
OK wrote connection string 'REQ
'.
Reading daemon response:
string(4) "ACK
"

Note the trailing '\n' to the ACK response, also note it's a string(4).

------------------------------------------------------------------------

[2005-11-03 22:06:28] sniper@php.net

Try 'var_dump($out);' before those 'if' clauses.


------------------------------------------------------------------------

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the rest of the comments, please view the bug report online at
    http://bugs.php.net/35086

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