#37263 [Com]: Escaping curly braces produces backslash in output.
| From: | judas dot iscariote at gmail dot com | Date: | Mon, 01 May 2006 19:32:26 +0000 |
| Subject: | #37263 [Com]: Escaping curly braces produces backslash in output. | ||
| References: | 1 | Groups: | php.bugs |
| Request: | Send a blank email to php-bugs+get-96453@lists.php.net to get a copy of this message | ||
ID: 37263
Comment by: judas dot iscariote at gmail dot com
Reported By: dbeckham at dealnews dot com
Status: Open
Bug Type: Scripting Engine problem
Operating System: Linux (2.6.14)
PHP Version: 5.1.2
New Comment:
this is not a bug, it's a behaviour change of the engine.
see.
http://bugs.php.net/bug.php?id=35527
and the documentation here:
"Before PHP 5.1.1, backslash in \{$var} hasn't been printed."
"(Use "{\$" to get a literal "{$")." [1]
[1] http://php.net/manual/en/language.types.string.php
Previous Comments:
------------------------------------------------------------------------
[2006-05-01 15:36:29] dbeckham at dealnews dot com
Description:
------------
When escaping curly braces in a string, the backslash characters are
included in any output.
Reproduce code:
---------------
<?
$test = "test";
echo "\{$test\}\n";
?>
Expected result:
----------------
The above output should be:
{test}
Actual result:
--------------
The actual output is:
\{test\}
------------------------------------------------------------------------
--
Edit this bug report at http://bugs.php.net/?id=37263&edit=1