#37538 [Opn->Bgs]: toString in sprintf/printf and %d modifier does't work as expected
| From: | helly@php.net | Date: | Sun, 21 May 2006 09:23:46 +0000 |
| Subject: | #37538 [Opn->Bgs]: toString in sprintf/printf and %d modifier does't work as expected | ||
| References: | 1 | Groups: | php.bugs |
| Request: | Send a blank email to php-bugs+get-97422@lists.php.net to get a copy of this message | ||
ID: 37538
Updated by: helly@php.net
Reported By: mfischer@php.net
-Status: Open
+Status: Bogus
Bug Type: Strings related
-Operating System: Linux
+Operating System: *
-PHP Version: 5CVS-2006-05-21 (CVS)
+PHP Version: *
New Comment:
Thank you for taking the time to write to us, but this is not
a bug. Please double-check the documentation available at
http://www.php.net/manual/ and the instructions on how to
report
a bug at http://bugs.php.net/how-to-report.php
%d is an integer conversion "(int)$obj" as apposed to a string
conversion that is served by __toString().
Previous Comments:
------------------------------------------------------------------------
[2006-05-21 05:40:36] mfischer@php.net
Description:
------------
The modifier %d doesn't work as one would expect sprintf/printf. When a
string is returned, it is always replaced %d with '1' instead of the
evaluated number of the __toString() output.
Consider this:
printf("%s %d", "4", "4");
will output "4 4", however if the parameters are replaced with an
object whith magic __toString() which returns "4", %d is not replaced
with 4 but with 1. It always returned 1, no matter what __toString()
returns.
Reproduce code:
---------------
class foo {
function __toString() {
return "4";
}
}
printf("%s %d\n", new foo, new foo);
printf("%s %d\n", "4", "4");
Expected result:
----------------
4 4
4 4
Actual result:
--------------
4 1
4 4
------------------------------------------------------------------------
--
Edit this bug report at http://bugs.php.net/?id=37538&edit=1