Bug #17655 Updated: key and intval on associative array are equal
| From: | mfischer@php.net | Date: | Sat, 08 Jun 2002 14:25:46 +0000 |
| Subject: | Bug #17655 Updated: key and intval on associative array are equal | ||
| References: | 1 | Groups: | php.bugs |
| Request: | Send a blank email to php-bugs+get-9851@lists.php.net to get a copy of this message | ||
ID: 17655
Updated by: mfischer@php.net
Reported By: msopacua@idg.nl
-Status: Open
+Status: Bogus
Bug Type: Arrays related
Operating System: Any
PHP Version: 4.2.1
New Comment:
Sorry, but the bug system is not the appropriate forum for asking
support questions. Your problem does not imply a bug in PHP itself.
For a list of more appropriate places to ask for help using PHP,
please visit http://www.php.net/support.php
Thank you for your interest in PHP.
Makes perfectly sense to me. key($arr) returns a "string". intval()
returns an int. The first if() tests string == int. PHP automatically
converts the string to an integer (which is 0 because there's no valid
number in key($arr) ). The second if() compares also the "types" of the
variables which do not match of course.
Previous Comments:
------------------------------------------------------------------------
[2002-06-08 09:04:03] msopacua@idg.nl
Sample:
<?php
$arr = array(
'string' => 'a string',
'anotherstring' => 'b string'
);
print(key($arr)."\t");
print(intval(key($arr))."\n");
if(key($arr) == intval(key($arr)))
{
print("Equal!\n");
}
else
{
print("Not equal\n");
}
if(key($arr) === intval(key($arr)))
{
print("Equal!\n");
}
else
{
print("Not equal\n");
}
?>
Output:
string 0
Equal!
Not equal
That really defeats the use of intval().
Confirmed on BSD/OS and Native windows/isapi.
------------------------------------------------------------------------
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Edit this bug report at http://bugs.php.net/?id=17655&edit=1