Re: Array and ID

From: Date: Thu, 02 Aug 2001 15:29:49 +0000
Subject: Re: Array and ID
References: 1  Groups: php.db 
Request: Send a blank email to php-db+get-11000@lists.php.net to get a copy of this message
Hi, > I have a drop-down menu that has been prepopulated with an array from a > column name CompanyName. What I need to do is take the CompanyName lookup > the CompanyID in the company table and insert the CompanyID into a row in a > table called contacts with a CompnayID column. [...] Is this a multiple or a single select? A quick and dirty thought: <?php $sql and $query as they were echo "<select name=\"company\">"; while ($row = mysql_fetch_array($query)) { echo "<option value=\"$row['CompanyID']\">$row['CompanyName']</option>"; // I didn't get the if-else statement you had here before. I think it is better to have // the id as the value and not the name. } ?> So if the from (which I assume you are using) is submitted you have $company with the CompanyID as its value which then can be inserted. If it is a multiple select you have to do it with an array but shouldn't be too tricky either hope it helps Johannes

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