Re: MySQL/PHP Troubles :( anyone have a solution?

You're not echoing anything back to the browser. For example change this: if ($action == "logout") { unset ($login_user); unset ($login_password); unset ($action); } to this: if ($action == "logout") { echo "You chose to log out<br>"; unset ($login_user); unset ($login_password); unset ($action); echo "Thanks, you are now logged out."; } It might also help prevent confusion if you indented your code for each level of curly brackets "{ }" you use. Having all your brackets flush left is tough to read. kind regards, bill hollett Kenneth Groth wrote: > Greetings, all :) I'm looking for a PHP god, or at least someone who has the > answer to my problem. I have a script for a login system that can handle > multiple users at > http://www.stoneneedle.f2s.com/loginsystem2.php3 ( > http://www.stoneneedle.f2s.com/loginsystem2.txt is the source > code, some may > have to click 'view source' in their browsers) - but it does not work.try > it-use handle "new_handle" with password "somepwd" ...that's one of > the > things in the MySQL database. oh, the login works great. but those options > in the select box don't - both take me to a nasty white screen of death when > I try to log out or change password ....the coding appears OK to a friend of > mine and excellent PHP coder. Is there something I missed? > -Stoney > P.S. - I know that the mysql_connect () is not given a password...because, > after all, I'm not putting in my MySQL database pass in there :P