Re: NEWBIE - Needs Assistance with Joins
| From: | Jonathan Hilgeman | Date: | Mon, 17 Sep 2001 18:39:40 +0000 |
| Subject: | Re: NEWBIE - Needs Assistance with Joins | ||
| References: | 1 | Groups: | php.db |
| Request: | Send a blank email to php-db+get-12512@lists.php.net to get a copy of this message | ||
You said you get a parse error - so I'm assuming that is a PHP parse error,
not an SQL error. Can you attach the entire problem file to an e-mail and
send it to me, along with the exact error message? I have a feeling that it
is something to do with the way you are retrieving the results in your PHP
code...
- Jonathan
"Cecily Walker Kidd" <babeephat@hotmail.com> wrote in message
news:babeephat-E89BE6.14425016092001@pb1.pair.com...
> Hello,
>
> I have two tables, one that contains an item id, album title name, and
> artist ID number. The second table is a list of artists, with an
> auto-increment artist ID.
>
> I want to join the two tables and have them output to a single PHP page.
> I was following along with the tutorial at
> http://www.webmasterbase.com/article/228/, and tried to modify
> it for my
> own needs. When I do this, I get a parse error on the line that starts
> with SELECT. Here's the code:
>
> $Link = mysql_connect ($Host, $User, $Password);
>
> $CDList =mysql_query(
> "SELECT artist_name, album_title ".
> "FROM artists, album_titles WHERE artist_id = aid");
>
>
> What am I doing wrong?
>
> Thanks in advance.