RE: [PHP-DB] What's wrong with my function? :(

I'm new to PHP but one thing I think might be happening is that maybe the changes aren't being made to a "global" (I'm a Java programmer) $sql so they aren't being kept. Does it actually break or is it not appending the additional string? I'd try printing out the $sql and see what you're getting - possibly at different stages of the program - like before and after you call your function. Good luck! -Natalie > -----Original Message----- > From: TorrentUK [SMTP:torrent@upyourpipe.com] > Sent: Tuesday, October 30, 2001 3:50 PM > To: php-db@lists.php.net > Subject: [PHP-DB] What's wrong with my function? :( > > Please could some take a look at this code and tell me why when I take my > IF > statements out of the function and put in them in the same place where I > call the function from they work, but as soon as I replace them with the > function name they don't? > > Appreciate any help. > torrent > > Here's the code... > > // Define the rating's filter > <?php > function RatingFilter () { > if ($br) {$sql.= " and beg_rate >= '2'";} > > if ($ir) {$sql.= " and int_rate >= '2'";} > > if ($ar) {$sql.= " and adv_rate >= '2'";} > > if ($sr) {$sql.= " and sbd_rate >= '2'";} > > } > ?> > > > if ($search) { > > include ('logon-inc.php'); > > $sql = "SELECT rsrt_name, ctry_name FROM resort_tbl WHERE > ctry_name='$country[0]'"; > > RatingFilter(); <--- If I put 'if' statement here instead it works > > > for ($n=1; count($country) > $n; $n++){ > > $sql.= " or ctry_name='$country[$n]'"; > > RatingFilter(); <-- Or here > } > . > . > . > . > } > > > > > -- > PHP Database Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-db-unsubscribe@lists.php.net > For additional commands, e-mail: php-db-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net