Re: Not a valid MySQL result resource

At 2:04 AM +0100 11/9/01, MPropre wrote:

<?php //.../... first part of the code is to connect to the right DB on a MySQL server. It works fine //This code to show the query. It runs well under MySQL and gives 1 result : $query="SELECT Login, Password FROM user WHERE user.login=''$login'' and user.password=''$password''"; //This var should contain a query result ressource: $result_query=mysql_query($query); //Here's my error message after executing:

Not so fast. Where's your error checking to verify that the query actually succeeded? if (!$result_query) {

    die ("Gee, I guess error checking is a good thing after all!"
         . mysql_error ());

}

// Supplied argument is not a valid MySQL result resource in this line: $result_table=mysql_fetch_array($result_query); // I thought that this var ($result_table) should contain the row of 2 cells //And I expected to read $result_table['login'] or $result_table[0] as the first cell of the row... // I any of you can help me, poor php newby... :o) Great thanks !! ?> -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: php-db-unsubscribe@lists.php.net For additional commands, e-mail: php-db-help@lists.php.net To contact the list administrators, e-mail: php-list-admin@lists.php.net