Re: Passing parameter in Paging

From: Date: Fri, 28 Dec 2001 14:03:22 +0000
Subject: Re: Passing parameter in Paging
References: 1  Groups: php.db 
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I don't understand why you won't use forms with buttons and hidden controls since you know about this solution. I have two suggestions along this line: 1. You probably don't want buttons on the page -- you may use image icons instead (similar to a tape recorder's "play" and "fast forward" for next page and last page) 2. If you don't want to use images either, you may use regular links with "href='javascript:document.nextPage.submit()'" where nextPage would be the form name with the page forward data -- and so on. HTH Bogdan Karthikeyan wrote: > Dear members, > I am querying a Mysql database, which will result in 100 of records. I want > to display 10 records in each page. First page it is working fine. When I > navigate to second page it is not working. > When I used hidden controls. Hidden controls send the details to next > page only by using submit button and not by hyperlink > When I used session variable. After one set of searching was over. When > I trying for second search string without closing browser, changing the > search string in the first search page it is still showing the old search > string, unless I close the browser. > Any solution for my problem > Thanking you > yours > Karthikeyan > > -- > PHP Database Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-db-unsubscribe@lists.php.net > For additional commands, e-mail: php-db-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net

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