Re: Sorting the output (opendir() and readdir())

Christian, > we have a directory with pics, that a user can associate with his data in a > form. we use opendir/readdir to show the directory contents. unfortunately, > this is not sorted. How can we achieve a listing in alphabetical order? > > this is our code: > > echo "<select name='image'>"; > echo "<option value=''>please select</option>"; > $fp = opendir("../pics/"); > while ($file = readdir($fp)) { > $selectfile="/pics/".$file; > if ($file=="." OR $file=="..") { } else { > $string_image .= "<option value='/pics/".$file."'"; > if ($selectfile==$image) { $string_image .= " SELECTED"; } > $string_image .= ">".$file."</option>"; > } > } > echo $string_image; > echo "</select>"; =readdir -- read entry from directory handle string readdir (resource dir_handle) Returns the filename of the next file from the directory. The filenames are not returned in any particular order. =so it is not possible to retrieve the filenames in alpha sequence. =Instead of taking the filenames directly from the readdir() and dropping them into the <option>, it may be necessary to put them first into an array/list. At the end of the while loop, the array could be sorted, and then another (for) loop implemented to copy the sorted list from the sorted array/list into the <option>s. =Regards, =dn