Re: properly a simple question
| From: | DL Neil | Date: | Sun, 13 Jan 2002 14:14:53 +0000 |
| Subject: | Re: properly a simple question | ||
| References: | 1 | Groups: | php.db |
| Request: | Send a blank email to php-db+get-15717@lists.php.net to get a copy of this message | ||
Barry,
This is properly a simple question but I can't figure it out.
=please don't ask im-proper questions, this is a family environment!!!
Lets say I've got there tables: table1(art_id,artist), table2(song_id,art_id,song),
table3(image_id,art_id,image).
What I'm trying to do is get 1 image displayed with the songs on that album displayed next to
it. All I can get
is 1image,1 song or 1 image per song (20 songs = 20 images).
=insufficient information. One (or a fourth) table will need to be populated with "album"
data.
=Have I misunderstood? Perhaps you could clarify your question with the code that you have already
attempted for
yourself (regardless of the fact that it isn't (yet) working), and maybe a demonstration of how
you would like
the result to appear from a set of sample data.
=As you say, it is probably quite simple. If you haven't RTFM, then try throwing
"join" at the manual's search
facility. Most of the examples show two-table joins, but a three-table join can be set up by
extending the WHERE
clause to relate two-pairs of tables (and so on...) joined by an AND.
=Regards,
=dn