Re: Re: Defining Arrays

From: Date: Sun, 13 Jan 2002 22:27:40 +0000
Subject: Re: Re: Defining Arrays
References: 1 2  Groups: php.db 
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Why don't you try $denc[]=substr($text,$i,1); Not to mention that $text[1] already is "h". Bogdan Thomas \"omega\" Henning wrote: > Something i forgot > when i echo("$denc[1]"); then it types Array out !!! > "Thomas "Omega" Henning" <tomi@mediasoft.ro> wrote in message > news:20020113153742.88846.qmail@pb1.pair.com... > > Hello, > > > > I'm curently working on an Encryption Bot for IRC that sends encrypted > > messages to other bots linked 2 it and users that are log into it. > > How i define an Array so i can use something like this > > <? > > $text="hello"; > > for ($i=0;$i<strlen($text);$i++) { > > $denc[$i]=substr($text,$i,1); > > } > > echo("$denc[1]"); > > ?> > > Theoraticly (in C++ point of view) that should print out "h". > > Any idias helps alot > > > > Thanks > > > > Thomas "omega" Henning > > > > > > > > -- > PHP Database Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-db-unsubscribe@lists.php.net > For additional commands, e-mail: php-db-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net

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