Re: php/msql

Mike wrote:

Hi, Hi Mike

I have the following code: while ($row = mysql_fetch_array($result)) { echo "<tr><td>".$row[0]."</td>\n"; echo "<td>".$row[1]."</td>\n"; $formatted=sprintf("$%s",$row[2]); echo "<td>" $formatted " </td></tr><br>"; } I get an error in the last line where I want to put $formatted into the last cell of a table if I // echo $formatted without the HTML tags it puts it at the top of the page. Ok Well have you checked thant you have a <table> at top and </table> at bottom of the code you've send us ?

The error is : Parse error: parse error, expecting ','' or ';'' Ok. I think it's cause you missed the . or , before and after $formatted.

Like at the second line : "blablabla".$something."blablabla"; It's for echoing the text, then the value of the variable, then text agin. It works with both . and , Try to do : echo "<td>",$formatted,'</td></tr><br>";

also: what does the "\n" mean at the end of the html tags? It's to break a line *in the source code* created by php (try to look the source of the page by your browser and see the diffrence)

I am new to PHP and have no seen that before. It's juste to produce "nice looking" source html code.

Thanks. Mike De rien ;o)

Tell us how it works ;-) Bye Fabien ILLIDE