Re: # of Records in Table
| From: | Zach Curtis | Date: | Wed, 23 Jan 2002 20:52:52 +0000 |
| Subject: | Re: # of Records in Table | ||
| Groups: | php.db | ||
| Request: | Send a blank email to php-db+get-16118@lists.php.net to get a copy of this message | ||
The last record should be whatever the last record is in the table. For
example, if there are 1000 records in the table which COUNT(*) will tell me,
how can I get the password for record 1000. The only thing I can do that
would probably work is two query statements, one selecting COUNT(*) and the
other selecting "password". What I don't like about this method is that I
would have to retrieve all of the passwords into an array, which I would
assume would be slow on larger tables. Ideally, I thought their would be a
way to do this operation in one select statement. Any thoughts?
Zach
-----Original Message-----
From: DL Neil [mailto:PHPml@DandE.HomeChoice.co.uk]
Sent: Wednesday, January 23, 2002 1:11 PM
To: Zach Curtis; php-db@lists.php.net
Subject: Re: [PHP-DB] # of Records in Table
Zach,
> What syntax can I use to determine how many records are in a MySQL table
and
> then retrieve the value of the field "password" for the last record? I
tried
> using some combinations of COUNT(*) and LIMIT with no success.
SELECT COUNT(*) will answer the first part. What did you try that lacked
success?
How do you define "last record"? We might need to see the table definition
to answer this.
Regards,
=dn