Re: Another dynamic sql.

From: Date: Fri, 25 Jan 2002 19:22:08 +0000
Subject: Re: Another dynamic sql.
References: 1  Groups: php.db 
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My example was a litle confusing here I see. My table have multiple price columns. something like this: carid convertible stationvagon etc. etc 1 100 100 100 ----- Original Message ----- From: "Gurhan Ozen" <c-gurhan.ozen@wcom.com> To: "Raymond Lilleodegard" <raymol@online.no>; <php-db@lists.php.net> Sent: Friday, January 25, 2002 8:11 PM Subject: RE: [PHP-DB] Another dynamic sql. > Seems like it will NOT work because you are selecting $car which is already > chosen by the user (i.e. which is a known value). I don't know how you laid > out your table but shouldn't your query be something like "SELECT price from > FROM varetabell where carid=$car" ?? > > Gurhan > > -----Original Message----- > From: Raymond Lilleodegard [mailto:raymol@online.no] > Sent: Friday, January 25, 2002 1:48 PM > To: php-db@lists.php.net > Subject: [PHP-DB] Another dynamic sql. > > > Hi all! > > I have this form with some choices: > > <form> > Enter how many cars you want:<input type="text" name="number" > > <select size="1" name="car"> > <option selected>ford</option> > <option>bmw</option> > <option>mercedes</option> > </select> > > And then I am trying to get the price out of a table in my database with > this code: > > > $sql = mysql_query("SELECT '$car' FROM varetabell where carid='$carid' > "); > $myrow= mysql_fetch_array($sql); > $x = $myrow["$car"]; > > $price = $x * $number; > > > Shouldn't this work? Or am I missing something here? > > > > Best regards Raymond > > > > -- > PHP Database Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-db-unsubscribe@lists.php.net > For additional commands, e-mail: php-db-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net > >

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