Re: variable interpolation in mysql queries

From: Date: Tue, 26 Feb 2002 23:16:39 +0000
Subject: Re: variable interpolation in mysql queries
References: 1 2 3  Groups: php.db 
Request: Send a blank email to php-db+get-17317@lists.php.net to get a copy of this message
Would it be faster if all you wanted was one variable, or your SQL statement only returned on cell? -- William Fong - wfong@mookandblanchard.com Phone: 626.968.6424 x210 | Fax: 626.968.6877 Wireless #: 805.490.7732 | Wireless E-mail: 8054907732@mobile.att.net ----- Original Message ----- From: "Bogdan Stancescu" <mgv@fx.ro> To: <bogdan@lanifex.com> Cc: "Ryan Snow" <snow@cosmic.utah.edu>; <php-db@lists.php.net> Sent: Tuesday, February 26, 2002 2:32 PM Subject: Re: [PHP-DB] variable interpolation in mysql queries : PS. You should consider using mysql_fetch_row() or at least : mysql_fetch_array() for perforance reasons. : : B : : Bogdan Stancescu wrote: : : > $query="query"; : > $result=mysql_query($query); : > $pd=mysql_result($result); : > : > Notice the zig-zag - $query is first on the left side, then on the : > right side, then $result is first on the left side, then on the right : > side. : > : > Bogdan : > : > Ryan Snow wrote: : > : >> Hi, Im kinda new to this list. Can anyone tell me what is the proper : >> way to interpolate my php variables into my mysql queries? : >> : >> I've been trying $query = "SELECT password FROM users WHERE : >> login='$login'"; : >> : >> : >> then: : >> mysql_query($result); : >> $pd = mysql_result($result); : >> : >> but I get a message that says: "Supplied Argument is not a valid : >> MySQL-Link resource" : >> : >> any ideas, anyone? : >> : > : > : > : > : : : : : -- : PHP Database Mailing List (http://www.php.net/) : To unsubscribe, visit: http://www.php.net/unsub.php :

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