Re: converting
| From: | Andrey Hristov | Date: | Fri, 12 Apr 2002 12:58:23 +0000 |
| Subject: | Re: converting | ||
| References: | 1 | Groups: | php.db |
| Request: | Send a blank email to php-db+get-18453@lists.php.net to get a copy of this message | ||
update some table set some_field='X' where ((some_field IS NULL) OR
(some_field!=""));
HTH
Andrey
----- Original Message -----
From: "Natividad Castro" <ncastro@cots.com>
To: <php-db@lists.php.net>
Sent: Friday, April 12, 2002 2:47 PM
Subject: [PHP-DB] converting
> Hi to all,
> I'm having a lot of problems doing something that for some of you might be
> simple.
> I'm selecting fields from a table that can have an 'A', 'B' or
> 'C' as their
> value
> e.g. FIELDNAME_1 = 'A'
> FIELDNAME_1 = 'B'
> FIELDNAME_1 = 'C'
> FIELDNAME_2 = 'A' AND SO ON
> what I'm trying to do is: if this field is no empty convert whatever value
> to 'X'. This part works fine only if the field has a value, but if the
> doesn't have a value, still giving an 'X'.
> here is some part of the code. any help is greatly appreciate.
>
> file://this is coming from my table
> $crromter = $query_data[CRRINTER];
> $crrhmintra = $query_data[CRRHMINTRA];
>
> file://this is what I'm trying to do
> <? if ($crrinter != "")
> {
> $crrinter_x = "X";
> }
> echo $crrinter_x;
>
>
> if empty($crrhmintra != "")
> {
> $crrhmintra_yy = "X";
> }
> echo ($crrhmintra;
>
> Thanks in advanced
> Nato
>
>
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