while X array. It will BE one BUG????

Hello. My name is Lauro. I am with a problem .. hehehe :) See my script : I select the code in the table agreement purchases as id_do user. . ======> $seleciona = pg_exec($login, "select produto_id from compras where id_usuario='$CLIENTE'"); if(!$seleciona){erro();} $linhas_=(pg_numrows($seleciona)-1); /*create an array with the values of $seleciona */ $dados=pg_fetch_array($seleciona, $n); /* loop to read the array $dados */ while (list($linhas_)= each($dados)) { /* to print for checking :)*/ print "$dados[$linhas_]\n"; /* whel.. I select then in another table values of a registration (still inside of the loop) that correspond to $dados[$linhas_]. */ $seleciona_2 = pg_exec($login, "select * from estoque where codigo='$dados[$linhas_]'"); if(!$seleciona_2){erro();} /* how many lines verifying found in the table. *\ $linhas_2=(pg_numrows($seleciona_2)); /*printing it resulted of the verification of lines */ print "<hr>$linhas_2<hr>\n"; /* liberating the memory of the second query */ pg_freeresult($seleciona_2); } <<============ :(... The problem is that my query doesn't recognize the variable $dados[$linhas_] Substituting the variable for the name of a true code. . the query works But $dados[$linhas_] it prints the name of a true code. Question : because it is not being printed inside of the query or is it been because the query doesn't recognize? ? I am using php4. . I needed the sessions. . in the 3 that worked... He would like codes to make the same thing. . To select a field of a table and with that result to select fields in other tables. . thank you.. for all.. :)