Re: error

From: Date: Tue, 07 May 2002 16:14:20 +0000
Subject: Re: error
References: 1  Groups: php.db 
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One thing I noticed quickly. You have too many opening ( on the line that says: while (($row = mysql_fetch_array($result, MYSQL_ASSOC)) 3 opening and 2 closing. This would cause a parse error. Without knowing which line is line 11, it is hard to say if there is anything else. HTH MB Chris Grigor <cgrigor@mweb.com> said: > Howdi guys > > any help on this would be greatful > > I have a page that submits to this script with a value of search > > but when I submit it gives me an error Parse error: parse error in /var/www/html/ul/mysql_fetch_array.php on line 11 > anyhelp here would be greatful, I dont see what the error could be > > Thanks > > Chris > > > <?php > > mysql_connect("localhost", "username", "password") or > die("couldnt connect"); > mysql_select_db("call_manage"); > > $query = "SELECT company_name, ticket_id, date from log_request where company_name like '%$search%'"; > $result = mysql_query($query); > > while (($row = mysql_fetch_array($result, MYSQL_ASSOC)) > printf ("Company: %s Ticket id: %s Date: %s", $row ["company_name"], $row["ticket_id"], $row["date"]); > > mysql_free_result($result); > ?> > > -- > PHP Database Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > --

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