newbie sunday morning not-enough-caffeine question

From: Date: Sun, 04 Jun 2000 16:57:50 +0000
Subject: newbie sunday morning not-enough-caffeine question
References: 1  Groups: php.db 
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Greetings. This simple little problem has been driving me nuts since I started this morning... hopefully one of you can help me. In essence, I need simply to read the variable "salesperson_code" from the "salespersons" table and write it into the "job_info" table. (The salesperson code may change in the future, so I want to record it in the job_info table as it stands today.) So far, no matter how I've tried to define "salesperson_code," I get only the value of "0" written to my job_info table. Here's a snippet of code: <?php mysql_connect ("localhost","root"); mysql_select_db ("bakergrfx"); $result = mysql_query("SELECT customer_code, customer_name, salespersons.salesperson_code, salesperson_name, csr from customer, salespersons where customer.salesperson_code = salespersons.salesperson_code and customer_code = '$customer_code'"); ... while($row = mysql_fetch_array($result)); } else {print "Sorry, no records were found!";} $sql = "INSERT INTO job_info (job_number, customer_code, salesperson_code) VALUES ('$job_number', '$customer_code', '$salesperson_code') "; $result = mysql_query($sql) or die("nope"); ?> Can anyone help me this morning? Thanks in advance, Kenn

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