Re: passing variables from one page to another
| From: | Matthew K. Gold | Date: | Mon, 08 Jul 2002 19:52:28 +0000 |
| Subject: | Re: passing variables from one page to another | ||
| References: | 1 | Groups: | php.db |
| Request: | Send a blank email to php-db+get-20396@lists.php.net to get a copy of this message | ||
You're right--I did leave out that end quotation mark. Unfortunately,
though, I'm still getting the same result after adding it.
best,
Matt
----- Original Message -----
From: Martin Clifford <MLC1@nrc.gov>
To: <mgold1@gc.cuny.edu>; <php-db@lists.php.net>
Sent: Monday, July 08, 2002 3:47 PM
Subject: Re: [PHP-DB] passing variables from one page to another
If that is your exact code, then you need to have an ending quote after the
query is written. Like this:
$query = "Select * from course, disc, instit, prof where course.CourseID =
$CourseID and course.DiscID = disc.DiscID and course.InstitID =
instit.InstitID and course.ProfID = prof.ProfID";
Martin
>>> "Matthew K. Gold" <mgold1@gc.cuny.edu> 07/08/02 03:40PM >>>
Hi Everybody,
Please forgive the basic nature of this question--I have looked at the
manual, but I found that much of it went over my head.
I'm trying to create a second level of a website that displays course
listings. The first level lists a bunch of courses. I'd like users to be
able to click on the title of a course to go to a page that contains details
about that course.
From what I understand, I should do this by making the title of the course
on the first page (courses.php) a link to the second page (courseinfo.php)
with a query string attached--so that the link would look like
<a href="courseinfo.php?CourseID=12">Accounting 101</a>
What I'm having trouble doing is coding the second page. Here's what I've
done. When I run this, I get a blank page in return...if anyone can help, I
would greatly appreciate it. Thanks in advance.
Matt
<?php
$db = @mysql_connect("host","user","pword");
mysql_select_db("dln", $db);
if ( !$CourseID ) {
print ("no course id included")
exit;
};
$query = "Select * from course, disc, instit, prof where course.CourseID =
$CourseID and course.DiscID = disc.DiscID and course.InstitID =
instit.InstitID and course.ProfID = prof.ProfID;
$result = mysql_query ($query);
echo "MySQL error number " . mysql_errno() . ": " . mysql_error();
print ("<table border=\"0\" cellpadding=\"5\"
class=\"default\">\n");
print ("<tr
bgcolor=\"#ff9900\"><th>$CourseID</th></tr><tr><td>$CourseTitle</td></tr></t
able>");
?>
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