Re: HELP NEEDED!

Your _Name1 in your SELECT doesn't have a $ in front of it. $_query = "select userName from users where userName = '$_Name1' "; or $_query = "select userName from users where userName = '".$_Name1."' "; Also after you query your database you have to get the results from your select. $_result after $_result = mysql_query($_query) or die(mysql_error()); will only hold false or true depending on the success of the query. Use mysql_result or mysql_fetch_array to get your results. Example: $userName = mysql_reqult($result,0); "Nik Alleyne" <nik@guyanachronicle.com> wrote in message news:20020713193517.67490.qmail@pb1.pair.com... > Hi there > I am having a problem querrying to my database. > I wish to check to see if a username is listed in the database so that I can > authenticate that individual. However, when I try to echo my $_result i'm > always getting 0 can someone please help. I think it should be either 1 or > 0. > > These are my scripts. > > This is my login pagepage > <?php > echo "<FORM name=_Form1 method=post action=test.php>"; > echo "<TABLE border=1 width=300 height=300>"; > echo "<tr>"; > echo "<td valign=top>"; > echo "<INPUT type=text value='' name=_Name1><br>"; > echo "<INPUT type=text value='' name=_Name2><br>"; > echo "<INPUT type=submit value='Submit' name=_submitButton>"; > echo "<INPUT type=Reset value='Reset' > name=_ResetButton><br>"; > echo "</td valign=top>"; > echo "</tr>"; > echo "</TABLE>"; > echo "</FORM>" > ?> > > This is my script processor > <?php > file://Script processor > mysql_connect("localhost", "nik", "playas") or > die("Could not connect to the server"); > > mysql_select_db("chronicleOnline") or > die("Could not connect to the database"); > > $_query = " select userName from users where userName='_Name1' "; > > $_result = mysql_query($_query) or > die(mysql_error()); > > if ( $_result = 0 ) > { > echo "$_result"; > } > else > { > echo "$_result"; > } > ?> > > P.S. I have no problem putting the data into the database, just this query. > > Thx > Nik > >