Re: HTML button display problem

In article <20020723034151.62776.qmail@pb1.pair.com>, markbm@hotmail.com says... > Thanks for the reply. When I added: > > <tr> > <td colspan=3 ><center> > > > <?php printf($result[PAYPAL_BUTTON]); > echo mysql_errno() . ": " . mysql_error() . "\n";?> > </center> > </td> > </tr> > > </td> </center> > </tr> > > It returned the value 0:, which to me is saying that its not pulling back > the data, but I'm not sure why. The data in the PAYPAL_BUTTON field is: > > <FORM method="POST" > > <P><INPUT type="submit" value="Submit" name="subBut"> > </FORM> > > I will paste the entirety of my code for your reference. I'm stumped. > Thanks again. > > Mark <?php printf($result[PAYPAL_BUTTON]); Should this not be <?php printf(mysql_result($result, 0, 'PAYPAL_BUTTON'); consistent with all your other code? May I recommend to you the use of mysql_fetch_array() and extract(), to make life a little easier? mysql_errno = 0 means no error in the last mysql query, and is best used immediately after the call to mysql; note however that I suggested mysql_error, which will return a string containing any error message returned by mysql. Again, use it immediately after your call to the database. -- David Robley Temporary Kiwi! Quod subigo farinam