RE: [PHP-DB] not a valid MySQL result
| From: | Peter Lovatt | Date: | Fri, 06 Sep 2002 18:25:04 +0000 |
| Subject: | RE: [PHP-DB] not a valid MySQL result | ||
| References: | 1 | Groups: | php.db |
| Request: | Send a blank email to php-db+get-21613@lists.php.net to get a copy of this message | ||
Hi
Couple of points, you probably have an SQL error,
I use
echo $query;
echo '<br>'.mysql_error();
which shows the query and the error
you use 'author-cat' in the table name
and 'author_cat' and 'author-cat' in the where clause which will throw an
error.
HTH
Peter
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-----Original Message-----
From: Wilmar Perez [mailto:wilmar.perez@caribe.udea.edu.co]
Sent: 06 September 2002 16:51
To: php-db mailing list
Subject: [PHP-DB] not a valid MySQL result
Hello guys
This is my first posting to the list, even though I've had some experience
with C++, these are my first steps with php and mysql.
Well, the thing is that I'm getting the following message:
Warning: Supplied argument is not a valid MySQL result resource
in /var/www/bva/new/main/colecciones.php on line 35
The code is shown below:
$query_cat = "select author_names || ' ' || author_surnames
from author, author-cat
where author_cat.cat_code = $code
and author.author_code = author-cat.author_code";
$result_cat = mysql_query($query_cat);
$num_results_cat = mysql_num_rows($result_cat); //This is line 35
I did the same with a simpler select sentence and it worked alright, so I
guess there's a problem with the select sentence but haven't been able to
find it.
Does anyone have an idea?
Thanks a lot for your help.
*******************************************************
Wilmar Pérez
Network Administrator
Library System
Tel: ++57(4)2105145
University of Antioquia
Medellín - Colombia
2002
*******************************************************
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