Re: Changing colors in table?

----- Original Message ----- From: Blue Tiger <bluetiger@mindspring.com> To: <php-db@lists.php.net> Sent: Tuesday, October 01, 2002 10:13 AM Subject: RE: [PHP-DB] Changing colors in table? : The blank table column comes from a blank MySQL database field...(I was : initially going to blob images from there to show status change). If you : know of a way to eliminate the database field and still show the status : of the values in a web table, please point me in the right direction. : >> I have a piece of code that displays an array from a MySQL table. One : >> field in the table is blank (and is displayed as an empty column of : >> cells) at the moment. I want to have the blank cells display an : image, : >> value, or change its background color based on whether the numerical : >> values in the previous 4 fields meet certain criteria or not. Make : >> sense? Maybe? : >> : >> An example of what I want to show: : >> If table 2 has a value that is less than 5, then the last cell : > displayed : >> changes color to reflect that. : >> If table 2 has a value that is between 5 and 10, then the last cell : >> displayed changes color to reflect that as well. Ryan, I understand you want to display the results of a db query in an html table. Maybe I misunderstand but it seems that this shouldn't be done by fiddling with the database table; fiddle with the html table instead open mysql server do select $result start while loop on mysql-fetch-array($result) { set $summedfields = (sum field values); if ($summedfields == 2) { $bgclr="red"; } else { $bgclr="blue"; } if ($blankfield == NULL) { $blankfield = "<img src='image.gif' etc>"; } iterate on table row use $blankfield and $bgclr as values the html table data cells e&oe Louise