array intersect with 2 arrays created from mysql

Hi, If anyone can help me with this I'd be most appreciative. I'm constructing 2 arrays of IDs from 2 different tables. Then I want to compare one to the other and only use the results that both arrays share in common to do a query loop that pulls the information for the related IDs to display. The error I get from the code below is: Warning: Argument #2 to array_intersect() is not an array in /usr/local/www/vhosts/trustbuild.co.nz/htdocs/partners_region.php on line 185 I cant see what is causing the problem. <<< Start of My Existing Code >>> $result = mysql_query("SELECT partner_id FROM partner_region WHERE region_id = '$r' ORDER BY partner_id"); if ($row = mysql_fetch_array($result)) { do {

    partner_region[] = $row['partner_id'];

} while ($row = mysql_fetch_array($result)); } if (count($partner_region) != 0) { array_unique($partner_region); } $result2 = mysql_query("SELECT id FROM partner WHERE type = '$t' ORDER BY id"); if ($row2 = mysql_fetch_array($result2)) { do {

    partner_type[] = $row2['id'];

} while ($row2 = mysql_fetch_array($result2)); } if (count($partner_type) != 0) { array_unique($partner_type); } $partner = array_intersect($partner_region, $partner_type); if (count($partner) != 0) { foreach ($partner as $p) {

    $result3 = mysql_query("SELECT * FROM partner WHERE id = '$p'");
    if ($row3 = mysql_fetch_array($result3)) {
      do {
        $company_name = $row3['company_name'];
        $contact_name = $row3['contact_name'];
        $physical_address = $row3['physical_address'];
        $postal_address = $row3['postal_address'];
        $city = $row3['city'];
        $phone = $row3['phone'];
        $fax = $row3['fax'];
        $email = $row3['email'];
        $url = $row3['url'];
        $gst_number = $row3['gst_number'];
        $company_age = $row3['company_age'];
        $services = $row3['services'];

$region = region($r);

        if ($count == 0) {
	  echo "<tr><td bgcolor='#FFFFFF'><a href='closeup.php?id=$id'>$region $company_name</a><br>Type: $company_type<br>Contact Name: $contact_name<br>".nl2br($physical_address)."</td></tr>";
          $count++;
        } else {
          echo "<tr><td bgcolor='#DDDDDD'><a href='closeup.php?id=$id'>$region $company_name</a><br>Type: $company_type<br>Contact Name: $contact_name<br>".nl2br($physical_address)."</td></tr>";
          $count--;
        }
      } while ($row3 = mysql_fetch_array($result3));
    }

} } else { echo "There are no listings for your criteria. Please try again.<br>"; } <<< End of My Existing Code >>> Thanks in advance for any help with this one, Nigel Dunn