RE: [PHP-DB] URGET HELP : Logic Help - for first record do_this f or each record after do_that

What about wrapping your logic in a counter? Set $count=1, if($count=1){do_this; then $count++;} else{do_that}. Wouldn't really add any overhead to your script since the counter only gets incremented once when the if() statement is true then stays at 2 and executes the else{} stuff after that. Pretty stupid solution and maybe not the most elegant, but you DID say URGENT. I just read Paul's post. This is pretty similar. > -----Original Message----- > From: Aaron Wolski [mailto:aaronjw@martekbiz.com] > Sent: Friday, October 25, 2002 2:54 PM > To: php-db@lists.php.net > Subject: [PHP-DB] URGET HELP : Logic Help - for first record > do_this for > each record after do_that > > > > Hey guys, > > Not really off topic as this involves some Db work as I have to query > the DB. > > Got a logic problem that was jumped dumped on me from UPS (dummys!). > > Basically I need to pull some records out of a database and for the > first record do_this logic and for each record after in the array > do_something_else logic. > > How would I approach this? > > something like: > > for ($first_record) { > > do_something; > > } else { > > do_something_else; > > } > > Any clues? > > Thanks! > > Aaron > > -----Original Message----- > > From: Graeme McLaren [mailto:mickel@ntlworld.com] > > Sent: Friday, October 25, 2002 2:40 PM > > To: php-db@lists.php.net > > Subject: [PHP-DB] Inserting checkbox data > > > > > > Hi all, I'm having a problem inserting a value from a > > checkbox into a MySQL DB. I can print out what the variable > > holds, the problem is it just won't go into the DB. Weird > > thing is when I login to SSH there isn't a NULL value for it > > instead that field is just blank. > > > > Anyone got any ideas what the problem is? > > > > > > The HTML that is used for the checkbox is: > > > > Gift Wrapping: <input type=checkbox Name=GiftWrapping[] Value=\"Y\"> > > > > > > So it should theoretically insert "Y" into the DB > > > > Here is the code that appears to be causing the problem: > > > > $number=count($GiftWrapping); > > for($a=0;$a<=$number;$a++) > > { > > echo $GiftWrapping[$a]; > > $GW = $GiftWrapping[$a]; > > echo $GW; > > } > > > > if ($Submit == "Submit") { > > $sql = "INSERT INTO SiteMember SET > > FirstName = '$FirstName', > > LastName = '$LastName' > > Username = '$Username', > > Password = '$Password', > > GiftWrapping = '$GW'"; > > } > > > > > > Thank you in advance for any help. > > > > Graeme :) > > > > > > Public Sub House() > > > > On Error Resume drink > > > > If Pint.empty = True Then > > Pint.refill > > Else > > Pint.drink > > End if > > > > stomach.add Pint > > > > MsgBox " I've had .... " & stomach.count & " Pints" > > MsgBox "VERY DRUNK" > > > > End Sub > > > > > > > -- > PHP Database Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > >