LIKE statement

From: Date: Sun, 03 Nov 2002 18:38:39 +0000
Subject: LIKE statement
Groups: php.db 
Request: Send a blank email to php-db+get-22928@lists.php.net to get a copy of this message
Hi, I've got a dilly of a problem. I'm probably doing something wrong but I don't know what. I'm trying to use the LIKE statement in a query where more than one word is used in with LIKE..e.g. select count(distinct itemid) from business where name or description like 'word1 word2 word3%' The problem I'm having is probably obvious to you but I don't know why this returns no matches but if i specify only 1 word in the LIKE statement then it returns a match. Am i not able to specify more than 1 word with LIKE or am I just doing it wrong? It has been designed to take input from a web form by the variable $search_string and then the query string is constructed from that e.g. $query = "select count(distinct itemid) from business where name or description like'" . $search_string . "'"; Any help or suggestions greatly appreciated.

Attachment: [application/pgp-signature] This is a digitally signed message part signature.asc
« previous php.db (#22928) next »