RE: [PHP-DB] Passing multiple form variable in PHP

I'm pretty sure all you have to do is name your select as an array like so: <select multiple name="icon[]"> Your selected values will come across as an array called $icon. If you need more info on this and how to use it, there's lots in the archives. That's where I found the info I needed. Good luck. Rich > -----Original Message----- > From: Stephen Rhodes [mailto:stephen.rhodes@scils.co.uk] > Sent: Tuesday, November 12, 2002 11:32 AM > To: php-db@lists.php.net > Subject: [PHP-DB] Passing multiple form variable in PHP > > > HELLO - this is probably a simple problem !!!!!! > > Wanting to use <select multiple ... > in a html form and pass > multiple value > into a php variable but does > not work. I only get a single value. Can you tell me what I > am doing wrong > ????? > > Does the multiple value get passed correctly in php ???? > > if ($task=="check") > { > printf("$icon"); > } > else > { > print '<form name="sqlform" method="post" > action="test.php?task=check"> > <font class="look2">Multiple Check:</font> > <select multiple name="icon"> > <option value="false">False</option> > <option value="true">True</option> > </select><br><br> > <input type="submit" name="submit" value="Submit" > border=0></form>'; > } > > Thanks > Steve R > > > > -- > PHP Database Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > >