RE: [PHP-DB] MySQL Array

From: Date: Thu, 05 Dec 2002 20:22:34 +0000
Subject: RE: [PHP-DB] MySQL Array
References: 1  Groups: php.db 
Request: Send a blank email to php-db+get-23852@lists.php.net to get a copy of this message
Why don't you post the actual data you are pulling FROM the Db.. then show HOW you want it formatted. Might be better for us to give you a solution or something. Aaron -----Original Message----- From: Art Chevalier [mailto:arthurc@scn.spawar.navy.mil] Sent: December 5, 2002 3:21 PM To: php-db@lists.php.net Subject: Re: [PHP-DB] MySQL Array Yes that makes sense, but it is pretty much the same thing I was doing and it's producing the same results. Its basically putting the first element in all 4 table cells. The thing is...I am only selecting from one field. Im trying to get the 4 elements of the column with each pass. So in essence I am trying to get the pointer to move down the array 4 positions within one pass through the loop. If I had any kind of logicl skills I probably could get it:) Art "Ryan Jameson" <RJameson@usa.ibs.org> wrote in message news:CC8578B824E74940BA5126774F49628D015A7E11@nathan.ibs.org... while ($ar = mysql_fetch_array($rs)) echo "<tr><td>". $ar['field1']."</td><td>".$ar['field2']."</td></tr>"; Make sense? -----Original Message----- From: Art Chevalier [mailto:arthurc@scn.spawar.navy.mil] Sent: Thursday, December 05, 2002 12:44 PM To: php-db@lists.php.net Subject: [PHP-DB] MySQL Array Hello, I am pulling one column out of a MySQL table in an array. I want to place each element into a HTML table 4 rows across. I am currently doing this with the mysql_fetch_array() function. How can I pull out 4 array elements in one pass through a while loop? Thanks Art Chevalier -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php

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