RE: [PHP-DB] MySQL Array
| From: | Aaron Wolski | Date: | Thu, 05 Dec 2002 20:22:34 +0000 |
| Subject: | RE: [PHP-DB] MySQL Array | ||
| References: | 1 | Groups: | php.db |
| Request: | Send a blank email to php-db+get-23852@lists.php.net to get a copy of this message | ||
Why don't you post the actual data you are pulling FROM the Db.. then
show HOW you want it formatted.
Might be better for us to give you a solution or something.
Aaron
-----Original Message-----
From: Art Chevalier [mailto:arthurc@scn.spawar.navy.mil]
Sent: December 5, 2002 3:21 PM
To: php-db@lists.php.net
Subject: Re: [PHP-DB] MySQL Array
Yes that makes sense, but it is pretty much the same thing I was doing
and
it's producing the same results. Its basically putting the first
element in
all 4 table cells. The thing is...I am only selecting from one field.
Im
trying to get the 4 elements of the column with each pass. So in
essence I
am trying to get the pointer to move down the array 4 positions within
one
pass through the loop. If I had any kind of logicl skills I probably
could
get it:)
Art
"Ryan Jameson" <RJameson@usa.ibs.org> wrote in message
news:CC8578B824E74940BA5126774F49628D015A7E11@nathan.ibs.org...
while ($ar = mysql_fetch_array($rs))
echo "<tr><td>".
$ar['field1']."</td><td>".$ar['field2']."</td></tr>";
Make sense?
-----Original Message-----
From: Art Chevalier [mailto:arthurc@scn.spawar.navy.mil]
Sent: Thursday, December 05, 2002 12:44 PM
To: php-db@lists.php.net
Subject: [PHP-DB] MySQL Array
Hello,
I am pulling one column out of a MySQL table in an array. I want to
place
each element into a HTML table 4 rows across. I am currently doing this
with the mysql_fetch_array() function. How can I pull out 4 array
elements
in one pass through a while loop?
Thanks
Art Chevalier
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