RE: [PHP-DB] print new account name on new account page?

I don't use the mysql functions anymore (look into php.weblogs.com) but I believe what you are looking for is $row['firstName'], not $firstName. (The extract MAY put them into variables for you but if it does, it's not necessary, just use the $row array. Also, tail the log file on your SQL server to make sure that the select is being executed properly. =C= * * Cal Evans * Stay plugged into your audience. * http://www.christianperformer.com * -----Original Message----- From: Addison Ellis [mailto:addison@bellsouth.net] Sent: Saturday, January 18, 2003 1:58 PM To: php-db@lists.php.net Subject: [PHP-DB] print new account name on new account page? hello, i have a form someone fills out. on submit it takes them to a new accounts page that say welcome new member. how can i get their name to print on the new page from the form they just filled out? i have been trying the following but it keeps giving me error messages regardless of how i manipulate the following. thank you for your time. addison <? include("config.php"); $sql = "SELECT firstName,lastName FROM accounts WHERE email='$logname'"; $result = mysql_query($sql) or die("Couldn't execute query 1."); $row = mysql_fetch_array($result,MYSQL_ASSOC); extract($row); echo " <head><title>New Account Welcome</title></head> <h2 align='center' style='margin-top: .7in'> Welcome $firstName $lastName</h2>\n"; ?> here is an example of the errors: Warning: extract() expects first argument to be an array in /users/infoserv/web/register/ca/new_account.php on line 82 -- Addison Ellis small independent publishing co. 114 B 29th Avenue North Nashville, TN 37203 (615) 321-1791 addison@bellsouth.net info@smipco.com subsidiaries of small independent publishing co. info@gloabaldog.com info@momandpocentral.com