RE: [PHP-DB] difference between two dates

> In my application I am accepting Day, Month and Year from a Select List. > What I want to do is calculate the age of the person based on the above > selection. > > $cboDD is the day variable > $cboMM is the month variable > $cboYY is the year variable > > I tried this : > > $dobtimestamp = mktime(0,0,0,$cboMM,$cboDD,$cboYY); > $todaytimestamp = time(); > $txtAge = ($todaytimestamp - $dobtimestamp)/86400; > > It does not give me the expected output. > > Can anybody suggest something ? Keep your mktime() as it is, that's correct. Then use something like this to calculate the age: $age = date('Y',$now) - date('Y',$dob) - ((date('z',$now)>=date('z',$dob)) ? 0 : 1); where $dob and $now are the appropriate unix timestamps that you've already got calculated with mktime() and time(). ---John W. Holmes... PHP Architect - A monthly magazine for PHP Professionals. Get your copy today. http://www.phparch.com/