RE: [PHP-DB] checking for empty array from a form field? grrrrrrrrrrr!

Ok... well When I select the "select product" which has a option value="" it tells me the count is one (1). If I select an ACTUAL product it tells me one(1) was select.. if I select two ACTUAL products it tells me two (2) products were selected. For SOME reason it doesn't seem to be recognizing that the option value="" is empty! Any more ideas?????? *sigh* Aaron -----Original Message----- From: Hutchins, Richard [mailto:Richard.Hutchins@Getingeusa.com] Sent: February 5, 2003 4:03 PM To: 'Aaron Wolski'; php-db@lists.php.net Subject: RE: [PHP-DB] checking for empty array from a form field? grrrrrrrrrrr! What about: count($arrayname) Should tell you how many items are in an array. > -----Original Message----- > From: Aaron Wolski [mailto:aaronjw@martekbiz.com] > Sent: Wednesday, February 05, 2003 4:04 PM > To: php-db@lists.php.net > Subject: [PHP-DB] checking for empty array from a form field? > grrrrrrrrrrr! > > > Argh !!!!!!!! > > > HOW does one check for an array being empty from a form > field?????????? > > Tried a billion different things and NOTHING works!!!! > > I've tried: > > if ($products == "\n") { > > echo "hello"; > } > > else { > > echo "bye"; > > } > > > if ($products == "") { > > echo "hello"; > } > > else { > > echo "bye"; > > } > > > > if (empty($products)) { > > echo "hello"; > } > > else { > > echo "bye"; > > } > > > if (!isset($products)) { > > echo "hello"; > } > > else { > > echo "bye"; > > } > > > if (count($products) == 0) { > > echo "hello"; > } > > else { > > echo "bye"; > > } > > > NOTHING works!!! > > Any help.. puuulease? > > Aaron > -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php