RE: [PHP-DB] User validation problem (newbie issue)

From: Date: Sat, 02 Sep 2000 18:29:45 +0000
Subject: RE: [PHP-DB] User validation problem (newbie issue)
Groups: php.db 
Request: Send a blank email to php-db+get-2586@lists.php.net to get a copy of this message
-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 Try something like this: $query = "SELECT * FROM users WHERE username='$username' AND pwd='$pwd'"; $result = mysql_query($sql,$conn); $rows = mysql_num_rows($result); if ($rows == 0) { // If no rows are returned, then the combination isn't correct. $access = 0; // $access is a boolean (0 - denied; 1 - granted) } elseif ($rows == 1) { // If one row is returned, then the combination is correct. $access = 1; } elseif ($rows >= 1) { // If more than one row is returned, we have issues! echo "<p>More than one row returned. That's not good.</p>"); $access = 0; } Untested, but I'm sure you get the gist of it. - ----------------------------------- Ollie Cook +44 (7946) 057 198 Programmer, XCalibre Communications - ----------------------------------- > -----Original Message----- > From: Charles Harvey [mailto:soops@threemoonsnetwork.net] > Sent: 02 September 2000 19:22 > To: php-db@lists.php.net > Subject: [PHP-DB] User validation problem (newbie issue) > > > Please help, > > I am trying to puzzle out how to validate users against a > database. In the > attached script, if the user name & pwd are incorrect, two errors > are returned and the else condition is met. How do I suppress > these errors, or > else test for them before they are echoed to the screen? > > //below line starts at line 8 for reference against the > errors messages > <?PHP > require("connect_inc.php"); > // This query works > $sql = "select * from users where username='$username' and > pwd='$pwd'" or > die ("Error in query"); > $result = mysql_query($sql) or die("invalid user or password"); > > echo "<br>"; > // assigns retrieved data to testable variables > $username_test = mysql_result($result,0,"username"); > $pwd_test = mysql_result($result,0,"pwd"); > > if($username_test=$username && $pwd_test=$pwd) { > > echo "it worked!!"; > > } > else { > echo "Sorry, it didn't work."; > } > > //this releases memory (on the client or server?) > mysql_free_result($result); > ?> > > Here are the errors received if the exact query data is not > correct: Warning: Unable to jump to row 0 on MySQL result index 2 > in > /home/httpd/html/php/members.php on line 16 > > Warning: Unable to jump to row 0 on MySQL result index 2 in > /home/httpd/html/php/members.php on line 17 > > I think the issue is how I am retrieving the username and pwd from > the query, but I haven't been able to figure out a better way. > Please advise a > better way to accomplish this? Thanks! > > Charles Harvey > Three Moons Network > http://threemoonsnetwork.net > 419-818-5260 > > > -- > PHP Database Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-db-unsubscribe@lists.php.net > For additional commands, e-mail: php-db-help@lists.php.net > To contact the list administrators, e-mail: > php-list-admin@lists.php.net > -----BEGIN PGP SIGNATURE----- Version: PGPfreeware 6.5.8 for non-commercial use <http://www.pgp.com> iQA/AwUBObFHGcPaWaNT0pVnEQLnpACgyeynJzvI5lVe5yYKmguVPFFbizMAoJ7T NgJLfeZofl8ANcD9ghbY1y7R =4vvs -----END PGP SIGNATURE-----

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