Re: date functions (generates parse error)

From: Date: Wed, 05 Mar 2003 17:33:57 +0000
Subject: Re: date functions (generates parse error)
Groups: php.db 
Request: Send a blank email to php-db+get-26105@lists.php.net to get a copy of this message
Sorry, I forgot to add the part at the bottom where I am calling the function ================================================================= <? function tips($weekstart){ $start = date('Ymd',strtotime($weekstart));   $query = "SELECT * FROM Rota WHERE date >= $start and date <= ($start + INTERVAL 6 DAY) ORDER BY staffid"; $result = mysql_query($query); while ($row = mysql_fetch_array($result)){ if ( isset ( $tips ) ){ if (isset ( $tips[$row[staffid]] ) ){ $hours = $row[finish] - $row[start]; $tips[$row[staffid]] = $tips[$row[staffid]] + $hours; } else{ $tips[$row[staffid]] = $row[finish] - $row[start]; } } else{ $tips = array('$row[staffid]' =>( $row[finish] - $row[start] ) ); } } return $tips; } function dbconnect(){ mysql_connect("localhost", "filterseveuk", "godisadj"); mysql_select_db("filterseveuk"); } dbconnect(); $date = "2003-03-02"; var_dump(tips($date)); ?> _________________________________________________________________ Express yourself with cool emoticons http://messenger.msn.co.uk

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