RE: [PHP-DB] Define()
| From: | Jonathan Villa | Date: | Tue, 18 Mar 2003 18:26:26 +0000 |
| Subject: | RE: [PHP-DB] Define() | ||
| References: | 1 | Groups: | php.db |
| Request: | Send a blank email to php-db+get-26449@lists.php.net to get a copy of this message | ||
Edwin,
There is no $ in front of the vars because it's a constant. $ signifies
a variable. A variable's value can change, a constant's value cannot.
---> Jonathan
-----Original Message-----
From: Edwin Boersma [mailto:edwin@orangeport.net]
Sent: Tuesday, March 18, 2003 2:43 AM
To: php-db@lists.php.net
Subject: Re: [PHP-DB] Define()
Where is the $-sign in front of the vars???
Edwin
Jonathan Villa wrote:
> Jim,
>
> I don't think that matters. One can escape into PHP in several ways
> (depending on the php.ini config of course)
>
> 1. <?php
> 2. <?
> 3. <script language="php"
> 4. <%
> 5. <?= (to echo something right away)
>
> Anyway, I tried that and it still doesn't work.
>
> ---> Jonathan
>
>
>
> -----Original Message-----
> From: Jim Hunter [mailto:jim@epiuniverse.com]
> Sent: Wednesday, March 12, 2003 2:59 PM
> To: jvilla@isdesigndev.com
> Subject: RE: [PHP-DB] Define()
>
>
> Looking at your source you are still missing the php in the script. it
> has to look like:
>
> <form action="<?php echo CTL_HOME_ROOT ?>" method="POST">
> note the php |||
>
> add this and try it again.
> Jim
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