Warning: Unable to jump to row...
| From: | Benjamin Trépanier | Date: | Mon, 31 Mar 2003 18:46:25 +0000 |
| Subject: | Warning: Unable to jump to row... | ||
| Groups: | php.db | ||
| Request: | Send a blank email to php-db+get-26752@lists.php.net to get a copy of this message | ||
Hi,
I'm trying to using a news script and improve somes with a query.
$req = MYSQL_QUERY("SELECT * FROM $TBL_NEWS");
$res = MYSQL_NUM_ROWS($req);
?>
<table border="0" width="400" cellspacing="0"
cellpadding="0">
<tr>
<td>
<img src="img/titre_calendrier.gif" alt="" width="404"
height="51"
border="0">
<?
$i!=$id_news_
$id = mysql_result($req,$i,"id");
$titre = mysql_result($req,$i,"titre");
$date = mysql_result($req,$i,"date");
$heure = mysql_result($req,$i,"heure");
$heure = str_replace(":","h",$heure);
$news = stripslashes(trim(mysql_result($req,$i,"news")));
?>
I want that my script show the content of the rows corresponding to my
Variable called: Id_News_
So the variable is moving well but when the scirpt is running and go to
display the row this code happend:
Warning: Unable to jump to row number X
Or
Currently he is always showing row #5...
I put my id_news_ in a echo and the variable is ok.. I really dont
understand
Thanks for your help!
BEn