RE: [PHP-DB] using a variable as values in an array

Instead of building a string in your loop do the assignment in the loop I have no idea what is being pulled from where, so I can't really give a good example -----Original Message----- From: Charles Kline [mailto:ckline@rightcode.net] Sent: Monday, March 31, 2003 1:25 PM To: php-db@lists.php.net Subject: [PHP-DB] using a variable as values in an array I am trying to build an array from the results of a query on a mySQL table. I am using a loop to create this string in a variable $mystring: '30'=>true, '20'=>true I then need to use it like this: $defaultValues['ib_article'] = array($mystring); It isn't working. I am sure there is a better method, can anyone point me in the right direction? thanks charles -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php