Re: Re: sending a form feed to a printer
| From: | Nathaniel Price | Date: | Wed, 02 Apr 2003 16:44:00 +0000 |
| Subject: | Re: Re: sending a form feed to a printer | ||
| References: | 1 2 | Groups: | php.db |
| Request: | Send a blank email to php-db+get-26812@lists.php.net to get a copy of this message | ||
What you are proposing is possible to do in html, if you add some Cascading
Style Sheets to the mix.
You will need to use the page-break-after attribute:
http://www.w3.org/TR/CSS2/page.html#propdef-page-break-after
It would look something like this (in plain html):
<table style="page-break-after: always">
<tr>
<td>row1col1</td>
<td>row1col2</td>
</tr>
<tr>
<td>row2col1</td>
<td>row2col2</td>
</tr>
...
<tr>
<!--'N' represents the number of rows you wish to print before a
form-feed -->
<td>rowNcol1</td>
<td>rowNcol2</td>
</tr>
</table>
<!--A printed page break would occur here-->
<table style="page-break-after: always">
<!--Wash, rinse, repeat-->
AFAIK, you'll have to close the table each time you want to print a line
feed, although if you want to keep your table together, you might try
putting the 'style="page-break-after: always"' attribute inside the
appropriate <tr> tag. No guarantees, tho, as I haven't tried it this way,
and it seems to go against the way CSS should work.
Also, not every browser supports these CSS attributes. You should be fine on
Netscape 6.0/Mozilla and IE 5 or better (not sure about IE, tho).
________________________________________
Nathaniel Price http://www.thornvalley.com
"Who is General Failure and why is he reading my hard drive?"
----- Original Message -----
From: "Jason S Motes" <jmotes@luhcares.org>
To: <php-db@lists.php.net>
Sent: Wednesday, April 02, 2003 8:15 AM
Subject: [PHP-DB] Re: sending a form feed to a printer
> form feeds don't work in html. It is interpreted as a space.
>
> Arthur Chevalier wrote:
> > Hello,
> >
> > I am having problems getting the \f (form feed) expression to work.
After a
> > certain amount of lines print I want to start printing the next line on
a
> > new sheet of paper. Any ideas of what I could be doing wrong. Below is
a
> > sample piece of my code. The bold code is where I am trying to issue
the
> > form feed.
> >
> > while($row = mysql_fetch_array($dbResult))
> > {
> > print("<TR>\n");
> > print("<TD class=\"tdborder\"><A
> > HREF=\"show_single_server.php?server_name=$row[0]\"
TARGET=\"text_float\">"
> > . $row[0] . "</TD>\n");
> > print("<TD class=\"tdborder\">". $row[1] .
> > "</TD>\n");
> > print("<TD class=\"tdborder\">". $row[2] .
> > "</TD>\n");
> > print("<TD class=\"tdborder\"><A
> > HREF=\"$PHP_SELF?mid_tier=$row[3]&db_rel=0\"
> > TARGET=\"text_float\">".
> > $row[3] . "</TD>\n");
> > print("<TD class=\"tdborder\"><A
> > HREF=\"$PHP_SELF?db_rel=$row[4]&mid_tier=0\"
> > TARGET=\"text_float\">".
> > $row[4] . "</TD>\n");
> >
> > $rowdata = $row[5];
> > if($rowdata == "")
> > {
> > print("<TD
> > class=\"tdborder\"> </TD>\n");
> > }
> > else
> > {
> > print("<TD class=\"tdborder\">". $row[5] .
> > "</TD>\n");
> > }
> > print("<TD class=\"tdborder\">". $row[6] .
> > "</TD>\n");
> > //print("</TR>\n");
> >
> > if($counter == "20")
> > {
> > $counter = "0";
> > print("</TR>\f");
> > continue;
> > }
> > else
> > {
> > $counter ++;
> > print("</TR>");
> > continue;
> > }
> >
> > }
> >
> >
>
>
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